x^2-27x+7=0

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Solution for x^2-27x+7=0 equation: 



x^2-27x+7=0

a = 1; b = -27; c = +7;
Δ = b2-4ac
Δ = -272-4·1·7
Δ = 701
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{701}}{2*1}=\frac{27-\sqrt{701}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{701}}{2*1}=\frac{27+\sqrt{701}}{2}
$

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